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Goraksha Dadhich
03 Apr 2019 10:26 AM study24x7 study24x7

 Find the fundamental period of 1+sin^2 (3π/5)n.

A

10/3

B

5

C

3π/5

D

None of the mentioned

Banking Railways UPSC Sciences
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  • geet sharma
    •  sin2(3π/5)n = (1-cos(6π/5)n)/2 = 1/2-1/2cos(6π/5)n ; period = 6π/(5*2π) = k/N = 3/5 ; N=5.
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    Reply 03 Apr 2019 12:01 PM
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