A diode circuit is so arranged that when the switch is open it’s KVL givesRi 1/C ∫i dt = 0When the switch is closed,Ri 1/C ∫i dt = VsVs is the dc supply voltage.The diode is so connected that it is forward biased when switch is closedThe circuit is mostly likely be a - Study24x7
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22 Mar 2023 01:00 PM study24x7 study24x7

A diode circuit is so arranged that when the switch is open it’s KVL gives
Ri+ 1/C ∫i dt = 0
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A

diode in parallel with Vs, switch, R & C

B

 diode in series with R, than parallel with Vs & C

C

diode in series with the switch, R, C & Vs

D

diode in series with R,C & Vs with the switch connected in parallel across Vs

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