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The assumed solution of the difference equation to the forcing equation x(n), called the particular solution of the difference equation is yp(n)=Kx(n)=Ku(n) (where K is a scale factor) Substitute the above equation in the given equation =>Ku(n)+aKu(n-1)=u(n) To determine K we must evaluate the above equation for any n>=1, so that no term vanishes. => K+aK=1 =>K=1/(1+a) Therefore the particular solution is yp(n)= 1/(1+a) u(n).