The percentage weight of Zn in white vitriol [ZnSO4.7H2O] is approximately equal to (Zn 65,S 32,O 16 and H = 1) - Study24x7
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81 followers study24x7 13 Apr 2021 12:46 PM study24x7 study24x7

The percentage weight of Zn in white vitriol [ZnSO4.7H2O] is approximately equal to (Zn 65,S 32,O 16 and H = 1)

A

22.65 %

B

23.6 %

C

33.655

D

32.56%

IIT Entrance NEET/Medical IIT-JEE
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